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https://confluence.cornell.edu/download/attachments/125812731/Graph.png?version=1&modificationDate=1316567430000 |
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$
M = F \times d = (8000 N) \times (4 m) = 32000 \mbox{ Nm}
$
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So this checks out. We also notice that the minimum moment 1.1278E-10 Nm. Because this value is over 1E-14 smaller that the largest value, it can be assumed to be zero to machine precision.
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