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 After being weighed, the tubing was removed and the length was measured, excluding the length of the plug inside the tube.  The diameter of the tube was calculated using this equation:

{latex}
\large
$$
D = sqrt {{{4m} \over {L\rho \pi }}}
$$
{latex}

Where

m = mass of water
L = length of tubing
rho = density of water at room temperature (.9982 g/cm^

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