Partial Differential Equation Toolbox |

pdegrad

Returns the gradient of a PDE solution

Syntax

-     [ux,uy]=pdegrad(p,t,u)
      [ux,uy]=pdegrad(p,t,u,sdl)

Description

`[ux,uy]=pdegrad(p,t,u)` returns the gradient of `u` evaluated at the center of each triangle.

Row i from 1 to N of `ux` contains

Row i from 1 to N of `uy` contains

There is one column for each triangle in `t` in both `ux` and `uy`.

The geometry of the PDE problem is given by the mesh data `p` and t. For details on the mesh data representation, see `initmesh`.

For a description of the format for the solution vector `u`, see `assempde`.

The optional argument `sdl` restricts the computation to the subdomains in the list `sdl`.

See Also

`assempde`

| pdegplot |  | pdeintrp |